Electrolysis overall equation 2

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[Lim Tze Khai]

Electrolysis of dilute NaCl aqueous solution with carbon electrode

Anode:    OH^- selected for discharge
   4OH^- --> 2H₂O + O₂ + 4e

Cathode:   H+ selected for discharge
   2H⁺ + 2e --> H₂

Overall equation:
Option 1:
2H₂O --> 2H₂ + O₂

or
Option 2:
4OH^- + 4 H⁺ --> 2H₂O + O₂ + 2H₂

Normally students will combine both 1/2 equation by equallise the number of electron to get opetion 1
Bbut both H⁺ and OH^- are from dissociation of H₂O, therefore by combining both H⁺ and OH^- to form H₂O and we get option 2.

Any comment?

[Liew Hui Lee]

I don't understand this statement "Normally students will combine both 1/2 equation by equallise the number of electron to get opetion 1 ".  Actually, according to the syllabus, option 2 is the correct overall equation by combining both half-equation : -

Reactant half-equation 1 + Reactant half-equation 2 -->  Product half-equation 1 +  Reactant half-equation 1  ( By cancel out the electrons ).

[Liew Hui Lee]

Repost with correction of typing error :

Reactant of half-equation 1 + Reactant of half-equation 2 -->  Product of half-equation 1 +  product of half-equation 2  ( By cancel out the electrons ).

[Wong Hee Ting]

My Opinion:

Option 2 is correct.

[Wong Pei Funn]

My Opinion:

Option 2 is correct.

but i asked my school chem teacher, she said option 1 should be correct. so, may i know which 1 is correct??

[Jackson de Rozario]

option 2 is correct.

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