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Author Topic: Oxidation & Reduction - Conversion from Fe(III) ion to Fe(II) ion - Confuse...  (Read 589 times)
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Wong Hee Ting
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« on: October 06, 2009, 02:06:25 PM »

During the reaction between FeCl3 and and Zn:

The ionic equation given in the ref book:

Zn + 2 Fe 3+--> Zn2++2Fe2+

This is the conversion of Fe (III) ion to Fe (II) ion.

I had checked, i can't find this equation actually, i think the correct ionic eq should be:

3 Zn + 2 Fe 3+ --> 3 Zn2++2 Fe

Anyone can tell me the which one is correct?  Huh
« Last Edit: March 03, 2010, 12:53:15 PM by Wong Hee Ting » Logged

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« Reply #1 on: October 07, 2009, 07:03:37 AM »

Mr. Wong, to what i understand, the first equation is the right one.

As the half equations go:

Fe3+ + e- --> Fe2+               (1)
Zn --> Zn2+ + 2e-                                (2)

(1) x 2

2Fe3+ + 2e- --> 2Fe2+            (3)

(3) + (2)
2Fe3+ + Zn --> 2Fe2+ + Zn2+
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« Reply #2 on: March 01, 2010, 10:39:36 PM »

For my opinion, both are correct. But in our lab, perhaps only the second chemical reaction that can happen because that process is a metal displacement. For the first one, i dare not confirm with u.
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Sim Thiam Huat
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« Reply #3 on: March 02, 2010, 05:07:28 PM »

mr. wong,
  your original equation is correct. this topic is regarding the oxidation from Fe2+ into Fe 3+. You find that
on both sides of the equation,
    a) the number of zinc and iron particles (regardless atoms or ions) are the same   
    b) the total positive charges on both sides are the same, i.e. 6 . Hence the equation is balanced in term of charges and number of particles.
T.Q.
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