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Author Topic: What is Ionic Equation for sulphuric acid and sodium hydroxide?  (Read 661 times)
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Wong Hee Ting
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« on: February 22, 2010, 04:46:36 PM »

What is Ionic Equation for the reaction between sulphuric acid and sodium hydroxide?

Chemical equation is:

H2SO4 + NaOH --> Na2SO4 + H2O

Then, what is the ionic equation?
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Wong Hee Ting
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« Reply #1 on: February 23, 2010, 08:45:10 AM »

What is Ionic Equation for the reaction between sulphuric acid and sodium hydroxide?

Chemical equation is:

H2SO4 + 2NaOH --> Na2SO4 + 2H2O

Then, what is the ionic equation?
From my opinion,
should be like this : 2H+ + 2OH- --> 2H2O

after simplify : H+ + OH- --> H2O
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Ting Tin Chung
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Wong Hee Ting
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« Reply #2 on: February 23, 2010, 05:07:50 PM »

okay, thanks for sharing.
 Smiley
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Eric Chong
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« Reply #3 on: February 24, 2010, 07:50:51 AM »

How about this? just my idea.
                2H+ + 2OH-  -> H2O
                2Na+ + SO42- -> Na2SO4
  Thus ,     2Na+ + SO42-+ 2H+ + 2OH- -> Na2SO4 + 2H2O
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Sim Thiam Huat
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« Reply #4 on: February 24, 2010, 04:36:18 PM »

The salt, sodium sulphate formed is soluble in water. Hence it will dissociate in solution to exist in the form of ions, Na+, SO4 2- , therefore the Na+ and SO42- ions on both sides of the ionic equations will cancel out leaving only H+  +    OH- -----  H2O
  In fact this is the common ionic equation for all neutralisation reactions involving acids and alkalis.
   Hope it helps.T.Q.
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