Heat of neutralisation

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[Wong Hee Ting]

The heat of neutralization is the heat released when one mole of water is formed from the reaction between an acid and an alkali.

For the neutralization reaction between a strong acid and a strong alkali, the heat of neutralization is -57.3 kJ mol-1. For example,

(i)
1/2 H2SO4 (aq) + NaOH(aq) --> Na2SO4 (aq) + H2O(l)  H = -57.3 kJ mol-1

(ii)
H2SO4 (aq) + 2 NaOH(aq) --> Na2SO4 (aq) + 2 H2O(l)    H =-114.6 kJ mol-1

Which thermochemical equation is correct? (i) or (ii)?

[Ting Tin Chung]

The heat of neutralization is the heat released when one mole of water is formed from the reaction between an acid and an alkali.

For the neutralization reaction between a strong acid and a strong alkali, the heat of neutralization is -57.3 kJ mol-1. For example,

(i)
1/2 H2SO4 (aq) + NaOH(aq) --> Na2SO4 (aq) + H2O(l)  H = -57.3 kJ mol-1

(ii)
H2SO4 (aq) + 2 NaOH(aq) --> Na2SO4 (aq) + 2 H2O(l)    H =-114.6 kJ mol-1

Which thermochemical equation is correct? (i) or (ii)?

for second equation, the H = -114.6 kJ. not -114.6kJmol^-1

from my opinion, both equation can accept.

[Adura Azlin b Ishak]

Ya. the first one is correct. heat released when 1 mol of water produce. that why, we use kJ mol -1.

the second, must used kJ only. because 2 mol water was produce. this only for strong ACID react with strong ALKALI.

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