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Author Topic: Question of Form 4 - Chapter 6 Coordinate Geometry  (Read 373 times)
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Jenna Tan
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« on: August 17, 2011, 02:33:36 PM »


The point A( 2a, a) , B( b ,c ) and C( 2b, 3c) are on a straight line . B divides AC internally in the ratio 3:4.
Express b in term c .

answer is : b=-4c

I only know that the formula for this question is
Quote
The point which divides the line joining two points
(x_{1}, y_{1}), (x_{2}, y_{2})
in the ratio m:n internally is
(\frac{mx_{2}+nx_{1}}{m+n}, \frac{my_{2}+ny_{1}}{m+n}).

Is that correct?

I have tried to solve the question using the formula above, but I did halfway only.
Because I don't know how to proceed by expressing b in term c.
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Jenna Tan
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Siao Fong Ting
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« Reply #1 on: August 17, 2011, 02:48:16 PM »

comparing the x-coordinate for point B and the x-coordinate obtained using the formula,  (6b+8a)/7 = b
             6b + 8a = 7b
             b = 8a -- (1)



comparing the y-coordinate for point B and the y-coordinate obtained using the formula, (9c+4a)/7 = c
            9c + 4a = 7c
                   4a = -2c
                    a = - (1/2)c  --(2)

substitude (2) to (1)
             b = 8 (-1/2)c
                = -4c
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Ting Siao Fong
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Jenna Tan
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« Reply #2 on: August 17, 2011, 03:16:59 PM »

comparing the x-coordinate for point B and the x-coordinate obtained using the formula,  (6b+8a)/7 = b
             6b + 8a = 7b
             b = 8a -- (1)



comparing the y-coordinate for point B and the y-coordinate obtained using the formula, (9c+4a)/7 = c
            9c + 4a = 7c
                   4a = -2c
                    a = - (1/2)c  --(2)

substitude (2) to (1)
             b = 8 (-1/2)c
                = -4c


Oh I see...
I did wrong from the beginning !  Embarrassed
Now I understand .
Thanks for your help !  Cheesy
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