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Author Topic: what is the solution for this question?  (Read 536 times)
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Yap Yee Soon
SMK Datin Onn Jaafar, Johor
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Batu Pahat


« on: October 31, 2011, 12:32:25 PM »

any different for the highlight sentence?

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SMK DATIN ONN JAAFAR
Yap Yee Soon
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Batu Pahat


« Reply #1 on: November 02, 2011, 04:57:16 PM »

why nobody answer? Sad
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Cheong Wooi Chun
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« Reply #2 on: November 04, 2011, 03:58:57 PM »

please be patient. eventually somebody will answer but it takes time. Many teachers and GCs are busy preparing last minute lesson for students.
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Cheong Wooi Chun
SMK St George
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Chong Lee Khim
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« Reply #3 on: January 01, 2012, 12:12:17 PM »

Don't be distracted by the highlighted sentence.  Just ignored it and answer as usual.  (use mean = np, P(X=r)= nCrprqn-r)
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SMK Serian
Wong Tok Hua

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« Reply #4 on: March 06, 2012, 01:05:50 PM »

Sorry, did not visit engkabang site for quite some time. In my opinion:

a) the mean now shd be 1 + 4(3/4) = 4, since he has solved the puzzle on Monday.

b) the probability that he answers correctly at least 3 days should be the probability that he solves the puzzle correctly for at least 2 days for the remaining 4 days since the outcome for Monday is certain. That means the answer shd be 4C2 (0.75)^2 (0.25)^2 + 4C3 (0.75)^3(0.25)^1 + (0.75)^4

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Wong Tok Hua
GC Matematik
SMK Bandar Bintangor.
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